Top best answers to the question «Does map return a new array»
The map() method returns an entirely new array with transformed elements and the same amount of data. In the case of forEach() , even if it returns undefined , it will mutate the original array with the callback .
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Definition and Usage The map () method creates a new array with the results of calling a function for every array element. The map () method calls the provided function once for each element in an array, in order. Note: map () does not execute the function for array elements without values.
.map () can be used to iterate through objects in an array and, in a similar fashion to traditional arrays, modify the content of each individual object and return a new array. This modification is done based on what is returned in the callback function.
array.map () calls the passed function with each element from the array and returns a new array containing values returned by that function. Your function just returns the result of the expression element.baz = condition ? foo : bar; which, depending on the condition, will
From MDC (emphasis mine): "map calls a provided callback function once for each element in an array, in order, and constructs a new array from the results. callback is invoked only for indexes of the array which have assigned values; it is not invoked for indexes which have been deleted or which have never been assigned values."In this case, x's values have not explicitly assigned values, whereas y's were assigned, even if it was the value undefined. – Martijn Mar 31 '11 at 15:03
map calls a provided callback function once for each element in an array, in order, and constructs a new array from the results Contrast that with the description of reduce: The reduce () method applies a function against an accumulator and each value of the array (from left-to-right) to reduce it to a single value.
callbackFn is invoked with three arguments: the value of the element, the index of the element, and the array object being mapped.. If a thisArg parameter is provided, it will be used as callback's this value. Otherwise, the value undefined will be used as its this value. The this value ultimately observable by callbackFn is determined according to the usual rules for determining the this seen by a function.. map does not mutate the array on which it is called (although callbackFn, if ...
From the callback parameters, you can access the current element, the current index, and the array itself. The map () function also takes in an optional second argument, which you can pass to use as this inside the callback. Each time the callback executes, the returned value is then added to a new array.